Question

In the circuit Fig. 16.16, find
(i) Total resistance of the circuit.
(ii) Total current flowing through the circuit.
(iii) The potential difference across 4 coulomb resistor.
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Answer 1

Answer:

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Answer 2

Solution :-

1) Two resistance are connected in parallel that is 6 ohm and 3ohm

Therefore ,

1/R in parallel = 1/R1 + 1/R2

Subsitute the required values,

1/R in parallel

= 1/6 + 1/3

= 1 + 2 /6

= 3/6

= 1/2

R in parallel = 2ohm

Now,

Total resistance = 2 + 4 = 6ohm

2) Now, we have to find the total current flowing in the circuit

Therefore,

V = IR

I = V/R

Subsitute the values,

I = 12/6

I = 2A

Hence, The total current flowing in the circuit is 2A.

3) Now, we have to find the pd across 4 ohm resistor

Therefore,

V = IR

Subsitute the required values,

V = 2 * 4

V = 8V

Hence, The potential difference across 4 ohm resistor is 8V $.$