In the circuit .Find the power supplied by 10v battery and power dissipated in 10 ohm resistor
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V=10v
R=10ohm
V=IR
I=V/R
=10/10
=1A
P=VI
=10×1
=10W
R=10ohm
V=IR
I=V/R
=10/10
=1A
P=VI
=10×1
=10W
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