Question

In the circuit given below
(a) What is the combined resistance?
(b) What is the p.d. across the combined resistance?
(c) What is the p.d. across the 3 Ω resistor?
(d) What is the current in the 3 Ω resistor?
(e) What is the current in the 6 Ω resistor?

Answer 1

Answer:

a.If different resistances are joined with each other such that there is only one path for the flow of electric current then the combination of such resistances is called Series Combination.

d.Current through 3 Ohm resistor × 3 Ohm = 30 V==> current though 3 Ohm resistor = 30 V/3 Ohm = 10 amp.

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Answer 2

Explanation:

Since the resistors are connected in parallel,the potential difference remains the same in each resistor.  

(a) The combined resistance,  $\frac{1}{R}=\frac{1}{R 1}+\frac{1}{R 2}=\frac{1}{3}+\frac{1}{6}=\frac{3}{6}$

$\text { So, } R=\frac{6}{3}=2 \text { ohm }$

(b) The potential difference across the combined resistor is, $V=I R$

    $V=6 \times 2=12 V.$

(c)  The potential difference across 3 ohm resistor, $v=V i . e ., 12 V.$

(d) The current in the 3 ohm resistor,$i 1=\frac{v}{R 1}=\frac{12}{3}=6 A.$

(e) The current in the 6 ohm resistor, $i 1=\frac{v}{B 2}=\frac{12}{6}=2 A.$