Physics, asked by navankursingh12345, 9 months ago


In the circuit given below, find the potential
difference between the points G and E.

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Answers

Answered by aditya012
22

Answer:

Potential difference across points G and E = 8V

Explanation:

First we need to find the resultant resistance of the circuit.

Formulas used :

Potential difference = Current x resistance. ( ohm's law)

For series combination of resistors :

R net = R1 + R2...

For parallel combination of resistors :

R net = [ 1/R1 + 1/R2 ...]^-1

Net resistance of CDA

= 4 + 4

= 8 ohms

Net resistance of CBA

= 4 + 4

= 8 ohms

Net resistance of CA

=[ 1/8 + 1/8]^-1

= [2/8]^-1

= 4 ohms -------------------(1)

Net resistance of AE

= 4 ohms ( since There is a single 4 ohm resistor in part AE) -------------------(2)

Similarly,

Net resistance of EFG

= 4 + 4

= 8 ohms

Net resistance of EHG

= 4 + 4

= 8 ohms

Net resistance of EG

=[ 1/8 + 1/8 ]^-1

= 4 ohms -----------(3)

Resultant resistance of the circuit

= (1) + (2) + (3)

= 4 + 4 + 4

= 12 ohms

We know that potential differences across the individual resistors of 4 ohms will add up to get 24V

Current flowing through the circuit ( I) = V / resultant resistance

= 24 / 12

= 2A

Potential difference across Point E and G = I x Net resistance of part EG.

= 2 x 4

= 8 volts

Answered by krishagrawal996
3

Answer:

The potential difference will be 8V

Explanation:

First we need to find the resultant resistance of the circuit.

Formulas used :

Potential difference = Current x resistance. ( ohm's law)

For series combination of resistors :

R net = R1 + R2...

For parallel combination of resistors :

R net = [ 1/R1 + 1/R2 ...]^-1

Net resistance of CDA

= 4 + 4

= 8 ohms

Net resistance of CBA

= 4 + 4

= 8 ohms

Net resistance of CA

=[ 1/8 + 1/8]^-1

= [2/8]^-1

= 4 ohms -------------------(1)

Net resistance of AE

= 4 ohms ( since There is a single 4 ohm resistor in part AE) -------------------(2)

Similarly,

Net resistance of EFG

= 4 + 4

= 8 ohms

Net resistance of EHG

= 4 + 4

= 8 ohms

Net resistance of EG

=[ 1/8 + 1/8 ]^-1

= 4 ohms -----------(3)

Resultant resistance of the circuit

= (1) + (2) + (3)

= 4 + 4 + 4

= 12 ohms

We know that potential differences across the individual resistors of 4 ohms will add up to get 24V

Current flowing through the circuit ( I) = V / resultant resistance

= 24 / 12

= 2A

Potential difference across Point E and G = I x Net resistance of part EG.

= 2 x 4

= 8 volts

Hope it help you...

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