Question

In the circuit given below four resistors R1 = 7 ohm,R2 = 10 ohm, R3 =30 ohm and R 4 = 5 ohm and a 12 volt battery are connected. calculate (i)the total resistance in the circuit (ii) the current in the circuit.​

Answer 1

Answer:

total resistence=52 Ohm

and total current in the circuit=0.23A

Explanation:

As we know that

Current(I)=Potential Difference(V)/Total. resistence(R)

=12/52

=3/13

=.0.23A

Answer 2

Answer:

The total resistance and current in the given circuit are equal to 52ohm and 0.23A.

Explanation:

Given:

$R_{1}=7ohm$

$R_{2}=10ohm$

$R_{3}=30ohm$

$R_{4}=5ohm$

V = 12V

Here,

The current in the given circuit is denoted by I.

The potential of the battery in the given circuit is denoted by V.

The total resistance of all resistance in the given circuit is denoted by $R_{t}$.

Now,

For Part one,

The formula used is,

$R_{t}=R_{1}+R_{2}+R_{3}+R_{4}\\R_{t} = 7+10+30+5\\R_{t}=52ohm$

Then,

For part two,

By the equation,

$I=\frac{V}{R_{t}} \\I=\frac{12}{52} \\I=0.23A$

So, the total resistance and current in the given circuit are equal to 52ohm and 0.23A.