Question

In the circuit one end has 20V and the other end of a battery has 30V. Due to this difference the amount of charge of 20C is flows through it. Find the Work done??​

Answer 1

Answer:

Work done by the circuit is 200 J

Explanation:

Given,

V2 = 30V

V1 = 20V

q = 20 C

Formula,

W = QV

Therefore,

W = (20)(30 - 20)

W = (20)(10)

W = 200 J