Question

in the circuit s1 is opened at t=0 and s2 is opend at t=4 msec determine I(t) for t>0​

Answer 1

Answer:

After a long time when switch S

1

is closed, the voltage entirely drop across the 20 Ω resistor.

The current in the circuit will be i=

R

V

=

20

1.5

=0.075amp

Energy in the inductor is U=

2

1

Li

2

When S

1

is opened and S

2

is closed, max energy in the capacitor will be stored when the charge on the capacitor is maximum.

∴

2

1

Li

2

=

2

1

C

q

max

2

⇒q

max

=

LCi

2

=0.075×

0.4×10

−3

×(4×10

−6

)

=4×10

−5

×75×10

−3

=3×10

−6

=3μC

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