Physics, asked by diachaudhary06, 1 year ago

In the circuit shown, a fuse in one bulb causes all the bulbs to go out. Which one is that bulb?

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narayan78: hlo

Answers

Answered by rohitpatiballa
3

the bulb due to which the circuits current may go out is the bulb one  as it blocks the way between the positive terminal of battery ,other bulbs and negative terminal of battery.So it has to be the one

Answered by bg1234
0

Answer:

Bulb 1 is the correct answer.

Explanation:

Bulb 1 is connected with the other four bulbs.

  • The current supply starts from E. We know that current in a circuit always flows from the positive end to the negative.
  • If the current flows in the circuit from bulb1 and then passes to bulb two and bulb three, which are connected in series, bulbs 4 & 5 are connected in parallel to bulb 1.
  • Thus, if a fuse in bulb one is off, then it causes the rest bulbs to switch off as the circuit breaks there and causes all the bulbs to stop working.

Series and Parallel connections:

There are two ways in which to connect more than two circuit components: series and parallel.

Series Configuration Circuit

  • A circuit is said to be connected in series when the same current flows through all the components in the circuit. In such circuits, the current has only one path.
  • If one bulb fuses, all the bulbs in the series do not light up.
  • In an electrical circuit, components are arranged in a line

Parallel Configuration Circuit

  • A circuit is said to be parallel when the electric current has multiple paths to flow through. The components that are a part of the parallel circuits will have a constant voltage across all ends.
  • Other components will function even if one component breaks down, each has its own independent circuit.
  • In an electrical circuit, components are arranged parallel to each other.

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