Question

in the circuit shown above,net current flowing through battery is
A)4 A
B)2 A
C)5 A
D)1 A​

Answer 1

Name the figure as shown in the attachment.

Now, the Current from the positive terminal (named as O), moves towards the point marked as G and then towards the point marked as C. If we see the path of current:-

• The current divides its path at G, then at C. Thus, they are in parallel combination.
• Now, the current travels without dividing from:

▪ G E F

▪ G H F

▪ C A B

▪ C D B

Thus, they are in a series combination.

• The effective resistance:-

▪ G E F: 5 + 5 = 10 Ohm

▪ G H F: 5 + 5 = 10 Ohm

▪ C A B: 5 + 5 = 10 Ohm

▪ C D B: 5 + 5 = 10 Ohm

• Overall resistance when all above four are in parallel combination:-

1/R = 4/10

R = 2.5 Ohm

V = 10 V [given]

I = V/R

=> I = 10/2.5

=> I = 4 A

Option (A) 4 A is right.