Question

In the circuit shown above, the value of r for which the current I is 0.5 ampere is

Answer 1

Heya!!

Since resistance across AD =

4&4 are in parallel nd in series with 4 ohm resistance.

= R = 4 + 2

= 6 ohms.

Then this is parallel with 4 ohms(BC) ..

= 1/R = 1/6 + 1/4

= 1/R = 5/12

= R = 2.4 ohms

This is in series with 1.6 ohm.. Hence total resistance = 2.4 + 1.6

= 4 ohms.

Since potential diff is same in parallel. So PD = 4 V

Since I = V/R

= 4/4 A

= 1 A

Suppose current in BC = i & current in AD = I.

Since i + I = 1 A,

4i = 6I

=) i = 3l/2

=) 3I/2 + I = 1

=) 5I/2 = 1

=) I = 2/5 A

= 0.4 A

Hope it helps uh!!

Please mark it brainiest answer dear