Question

In the circuit shown all five resistors have the same value 200 ohms and each cell has an emf 3 volts. Find open circuit voltage and the short circuit current for terminals A and B.

Answer 1

The voltage is - 5.4 V and the current is 0.01 A

Explanation:

Let the current in loop be i

KVL equation = APQA

=> i x 200 + 3 - i x 200 + 3 - i x 200 - i x 200 - 3

    - i x 200 = 0

=> 5 x i x 200 = 6 => i = 6 /1000

Now, VA + i x 200 + 3 + i x 200 = VB

=> VA - VB = - [ i x 400 +3]

=> VA - VB = - [ 6/1000 x 400 + 3] = - 5.4 V

After short circuiting, no current will flow.

Now i = 6V/ 600 Ω  = 0.01 A

Thus the voltage is  - 5.4 V and the current is 0.01 A

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