Question

In the circuit shown below current I flowing through 6 ohm resistance and voltage drop V across 3 ohm resistance respectively are​

Answer 1

Answer:

R1=3ohm R2=4ohm, R3=6ohm

As the resistors are connected in parallel

1/Rtotal=1/3+1/4+1/6

1/Rtotal=(4+3+2)/12

1/Rtotal=9/12

Rtotal=12/9

Rtotal=4/3 ohm

Total current=Voltage /Rtotal

Itotal=2/(4/3)

Itotal=6/4

Itotal=3/2 Ampere

For resistance in the parallel,  the voltage across each resistor is the same, and the total current is the sum of the flow through each resistor.

Current through R1=V/R1=2/3 Ampere

Current through R1=V/R3=2/6=1/3 Ampere

Answer 2

Answer:

2/3 A and 4 v answer to this question