in the circuit shown below, the cell has an e.m.f of 10V and internal resistance of 1 ohm l. the other resistances are shown in figure. The potential difference Va - Vb is
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Answer:
Va - Vb = - 2
Explanation:
in the circuit shown below, the cell has an e.m.f of 10V and internal resistance of 1 ohm
Equivalent resistance
1 + 1/ ( 1/(4 + 2) + 1/(2 + 4) ) + 1
= 1 + 6/2 + 1
= 5
Current flowing = 10/5 = 2 A
Current flowing through 4Ω & 2Ω = 1A
E - Va = 2 * 1 + 1 * 4
=> E - Va = 6 - eq 1
E - Vb = 2 *1 + 1 *2
=> E - Vb = 4 - eq 2
Eq2 - eq 1
=> Va - Vb = 4 - 6
=> Va - Vb = - 2
Va - Vb = - 2
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