In the circuit shown below
The potential difference between point A and B is
(1) Zero
(2) -2 V
(3) 4 V
(4) +2 V
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Answer:
In Line of A
2 and 4 are in series so=2+4=6 ohm
In Line Of B
Again 2+4=6 ohm
No Resistance across AB is equal and Parallel
1/R(equivalent)=1/6+1/6=1/3 ohm
R(Equivalent)=3
Now,
All the other resistors aee in series
3+6+1=10 ohm
Now we know that electric potential difference
V=i×R
20=i×10
i=+2 Ampere
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