Physics, asked by chakrabortypoulami31, 9 months ago

In the circuit shown below
The potential difference between point A and B is
(1) Zero
(2) -2 V
(3) 4 V
(4) +2 V​

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Answers

Answered by dewanganajay1875
1

Answer:

In Line of A

2 and 4 are in series so=2+4=6 ohm

In Line Of B

Again 2+4=6 ohm

No Resistance across AB is equal and Parallel

1/R(equivalent)=1/6+1/6=1/3 ohm

R(Equivalent)=3

Now,

All the other resistors aee in series

3+6+1=10 ohm

Now we know that electric potential difference

V=i×R

20=i×10

i=+2 Ampere

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