Physics, asked by dasswayam50, 10 months ago

In the circuit shown below, the ratio of reading of ammeter A1, A2 and A3 is.

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Answers

Answered by Kush800031
3

Answer:4:5:40

Explanation:

Answered by nidaeamann
5

Answer:

A1 : A2 : A 3 = 0.08 : 0.1 : 0.8

Explanation:

Let us first calculate the voltage across each limb of the given circuit

Calculating for A3;

Voltage across 40 ohm = 32 v (as this is parallel to main limb)

Current through A3 = 32/40 = 0.8 Amp

Effective parallel resistance of 100 and 25 is 20

Effective parallel resistance of (20+100) and 120 is 60

It means that 32V is to be distributed among 100 and 60 ohm

Voltage across A2 = 32 x 60/160 = 12

Current through A2 = 12/120 = 0.1 Amp

Now voltage across A1 would be = 12 x 20/120 = 2 V

Current through A1 = 2/25 = 0.08

A1 : A2 : A 3 = 0.08 : 0.1 : 0.8

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