Question

In the circuit shown below, the voltmeter reads 10 V.
(a) What is the combined resistance?
(b) What current flows?
(c) What is the p.d. across 2 Ω resistor?
(d) What is the p.d. across 3 Ω resistor?

Answer 1

Current Flowing in the Circuit is 2 Amperes

Explanation:

Given values are ,

• Current, I = 6 V

• Resistance, $R_1 = 2\ \Omega$

• Resistance, $R_2 = 3\ \Omega$

a.) Combined Resistance, $R_t_o_t = 2 + 3 = 5\ \Omega$

b.) As per Ohm's Law, V = IR

or I =  $\frac {V}{R_t_o_t}$

= $\frac {10}{5} =$ 2 A

c.) Potential Difference across the $2\ \Omega\ resistance = I \times R_1$

= $2 \times 2$ = 4 V

d.) Potential Difference across the $3\ \Omega\ resistance = I \times R_2$

= $2 \times 3$ = 6 V

Current Flowing in the Circuit is 2 Amperes

Answer 2

I = 6v

R1 = 2 Ω , R2 = 3 Ω

(a) Combined resistance, R tot = 2 + 3 = 5 Ω

(b) I = v/Rtot = 10/5 = 2A

(C) p.d. across 2 Ω resistor = I × R1 = 2 × 2 = 4v

(d) p.d. across 3 Ω resistor = I × R2 = 2 × 3 = 6v