in the circuit shown below, voltage drop across 5 ohm resistance is
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1.5 V
Step-by-step explanation:
Given The resistance in series are 5 ohms and 15 ohms. So it will be 20 ohms. Now 10, 20 and 60 ohms are in parallel.
Since we know 1/R = 1/R1 + 1/R2 + 1/R3
So 1/R = 1/10 + 1/20 + 1/60 ohms
1/R = 6 + 3 + 1 /60
So R = 6 ohms
The current is given as 1 A
V = IR
= 6 x 1 = 6 V
So across 20 ohms there is 6 V
So current flowing through 5 ohms and 15 ohms = 6/20 = 0.3 amps
Therefore voltage drop across 5 ohm will be 5 x 0.3 = 1.5 V
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