Question

in the circuit shown below, voltage drop across 5ohm resistor is​

Answer 1

5Ω & 15 Ω are in series

so effective resistance = 20Ω

10 , 20 & 60 Ω resistance are in parallel

so effective resistance of circuit

= 1/(1/10 + 1/20 + 1/60)

= 60/(6 + 3 + 1)

= 60/10

= 6 Ω

Current = 1A

Voltage = 6 * 1 = 6 V

6V across 20 Ω

current through 5Ω & 15Ω = 6/20  = 0.3A

Voltage drop across 5Ω = 5 * 0.3 = 1.5V