CBSE BOARD XII, asked by vivek110995, 5 hours ago

In the circuit shown capacitor c1 is charged to 50 v and c2 is charged to 20 v after charging th​

Answers

Answered by samarthcv
1

Answer:

When switches are open, charges on the capacitor are Q

1

=50×2=100μC and Q

2

=20×2=40μC

when switches are closed, both capacitor will be in parallel

so potential and capacitance for both capacitor will be same. Hence Q will also be same

Q

1

=Q

2

let charge xμC flowing from C

1

toC

2

−(Q

1

−x)=Q

2

−x

−(100−x)=40−x

2x=140 x=70μC

70μC charge will flow in the circuit. Hence charge passing through S

1

,S

2

and S

3

is 70μC

Explanation:

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