In the circuit shown capacitor c1 is charged to 50 v and c2 is charged to 20 v after charging th
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Answer:
When switches are open, charges on the capacitor are Q
1
=50×2=100μC and Q
2
=20×2=40μC
when switches are closed, both capacitor will be in parallel
so potential and capacitance for both capacitor will be same. Hence Q will also be same
Q
1
=Q
2
let charge xμC flowing from C
1
toC
2
−(Q
1
−x)=Q
2
−x
−(100−x)=40−x
2x=140 x=70μC
70μC charge will flow in the circuit. Hence charge passing through S
1
,S
2
and S
3
is 70μC
Explanation:
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