Question

in the circuit shown, current flowing through 25V cell is ​

Answer 1

Given in the circuit shown, current flowing through 25V cell is ​

We are given

e1 = 10 v, e2 = 5 v, e3 = 20 v, e4 = 30 v and r1 = 5 , r2 = 10, r3 = 5 and r4 = 11 ohms

We know that

1/r = 1/r1 + 1/r2 + 1/r3 + 1/r4

1/r = 1/5 + 1/10 + 1/5 + 1/11

1/r = 65 / 110

r = 110/65

r = 1.692 ohms

We know that

E = (e1/r1 - e2/r2 + e3/r3 - e4/ r4) x r

E = (10/5 - 5/10 + 20/5 - 30/11) x 1.692

E = (220 - 55 + 440 - 300)/110 x 1.692

E = 4.691 v

Using Kirchoff's law for second loop we get

- 25 + 4.691 + i(1.692) = 0

 i is approximately 12 amps or i = 12 amps