In the circuit shown here, the point c is kept connected to point a till the current flowing through the circuit becomes constant. Afterward, suddenly, point c is disconnected from point a and connected to point b at time t = 0. Ratio of the voltage across resistance and the inductor at t = l/r will be equal to :
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The ratio of the voltage across resistance and the inductor at t = l/r will be equal to -1.
Explanation:
Applying Kirchoff's law,
-iR -Ldi/dt = 0
−Ldi/dt=iR
-di/i = R/L x dt
Hence we will get,
i = i o × exp(−R/L×t)
at t = L/R
i= i o / e
Hence V(R) = -io R/e
V(L) = -Ldi/dt
This becomes ioR/e
Hence ratio = -1
Thus the ratio of the voltage across resistance and the inductor at t = l/r will be equal to -1.
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