Question

In the circuit shown here, the point c is kept connected to point a till the current flowing through the circuit becomes constant. Afterward, suddenly, point c is disconnected from point a and connected to point b at time t = 0. Ratio of the voltage across resistance and the inductor at t = l/r will be equal to :

Answer 1

The ratio of the voltage across resistance and the inductor at t = l/r will be equal to -1.

Explanation:

Applying Kirchoff's law,

-iR -Ldi/dt = 0

−Ldi/dt=iR

-di/i = R/L x  dt

Hence we will get,

i = i o  × exp(−R/L×t)

at  t = L/R

i=   i o / e

Hence V(R) = -io R/e

V(L) = -Ldi/dt

This becomes ioR/e

Hence ratio = -1

Thus the ratio of the voltage across resistance and the inductor at t = l/r will be equal to -1.

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State Kirchhoff's rules. Explain briefly how these rules are justified. ?

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