Question

In the circuit shown if the power consumed in 6 ohm resistor is 24 W then the power consumed in 4 ohm resistor is.

Answer 1

P = V^2/R
FOR 6 ohm resistor
P = V^2/6
24 = V^2/6
V^2 = 24 × 6
V = 12
so
for 4 ohm resistor
P = V^2/R
= (12×12)/4
P=36 watt

Answer 2

Answer:

The power consumed in 4 ohm resistor is 64 watt.

Explanation:

Given that,

The consumed power across 6 Ω = 24 W

P = 24 W

We have a formula of current and power across resistor.

$P=I^2R$

$24=I^2\times 6$

I=2 A

Current in lower loop is 2 A

Now, we will find the voltage across lower loop.

V=IR

Net resistance, R = 6+12 = 18 Ω

Net Current, I = 2

Voltage, V=2 x 18 = 36 volts

In parallel voltage difference equal.

Thus, Voltage across upper loop would be same (36 volt)

Net resistance at upper loop, R = 9 Ω

Voltage, V=36 volt

I=V/R

I=36/9 = 4 A

Now, we will find power consumed by 4 ohm.

$P=I^2R$

$P=4^2\cdot 4$

$P=64\ W$

Hence, The power consumed by 4 ohm resistance is 64 W