Question

In the circuit shown in figure, charge on C1 is 20uC. The potential difference between point A and B is​

Answer 1

Explanation:

10 volt is the answer , plz put thanks if satisfied

Answer 2

Answer:

The potential difference between points A and B is 10 volts.

Explanation:

The potential of the capacitor can be calculated as,

$V=\frac{Q}{C}$       (1)

Where,

V=potential difference across the capacitor

Q=charge on the capacitor

C=capacity of the capacitor

From the question we have,

C₁=2μF

C₂=2μF

C₃=3μF

Q₁=20μC

So, the voltage across C₁ will be,

$V_1=\frac{20\mu C}{2\mu F}$

$V_1=10volt$       (2)

The third capacitor i.e.C₃ will be short-circuited as it is connected by the plain wire.

Now the capacitors C₁ and C₂ will be in parallel. And we know that in the parallel combination the voltage across the capacitors remains the same.

Hence, the potential difference between points A and B is 10 volts.