Question

In the circuit shown in figure the current measured by ammeter is​

Answer 1

Answer:

3 A

Explanation:

total potential=50V

50= √Vr^2 + ( Vc^2 + Vl^2)

=√ Vr^2 + 40^2

2500= Vr^2 + 1600

Vr^2 = 900

Vr = 30

I= V/R

 = 30/10

 =3A