In the circuit shown in figure, the power which is
dissipated as heat in the 6 12 resistor is 6 W. What
is the value of resistance R in the circuit ?
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In addition to Sunder’s fine answer, we can effect a solution several different ways. Let’s look at an alternative path to the solution. Since we have a simple series circuit, we can apply the voltage divider relation,
V1=R1R1+R2Vs
Now that we have V1 we may apply the relation,
P1=V21R1
if we assume R1=6 Ohms and R2 = 9 Ohms with Vs = 120 V we have,
V1=6Ω6Ω+9Ω120V=48V
P1=(48V)26Ω=384W
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