Question

In the circuit shown in the figure, current through the resistance R3 is​

Answer 1

Answer:

12 ohm

Explanation:

Answer 2

Current through the resistance R3 is​ $\frac{8}{3}$ A

Given : The circuit diagram

To Find : Current through the resistance R3

Solution : The current through the resistance R3 is $\frac{8}{3}$ A

Current from the branch A will divide into two parts i1 and i2 , i1 goes through the resistor 10 ohm and i2 goes through the resistor 5 ohm

Since the resistor 10 ohm and 5 ohm are in parallel connection they have same potential

V = IR

So 10 × i1 = 5 ×i2

i2 = 2 × i1

But the total current is 8 A

so i1+i2 = 8

i1 + 2i1 = 8

3i1 = 8

i1 = $\frac{8}{3}$

i2 = $\frac{16}{3}$

Current i2 will again distribute in two direct at point D

Since resistance in branch BD is same as the resistance is branch DC so equal amount of current will be distributed in both the branch

So i2 will be distributed as $\frac{i2}{2}$ in both the branches

So current through resistance R3 is $\frac{i2}{2}$ = $\frac{16}{6}$ = $\frac{8}{3}$

So current through the resistance R3 is​ $\frac{8}{3}$ A

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