in the circuit shown in the figure the cell has emf=10v and internal resistance =1ohm..the current through 3ohm resistor and 4ohm resistor is?
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So current across 3 ohms will be 1A
Since the current will be divided symmetrically in both the branches,
In first branch it will be halved is 0.5 A
After that it will be halved again i.e. 0.25 A.
Thus the current across 4 ohms would be 0.25 A
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