Question

In the circuit shown in the following figure, the potential difference between points A and B

will be​

Answer 1

Answer:

Explanation:

You mean potential difference between C and D

There are two wire connected parallel so there will be equal potential difference between C and D = 2 V , whether you go by upper wire or lower.

Extra/useless things here

Go C to D by upper wire resistances are in series R(upper) = 5 + 5 + 5 = 15

Go C to D by lower wire resistances are in series R(lower) = 5 + 5 + 5 = 15

Now as upper and lower wire are parallel between C and D

$\frac{1}{R(net)} = \frac{1}{R(upper)} + \frac{1}{R(lower)}$   $= \frac{1}{15} + \frac{1}{15} = \frac{2}{15}$

$R(net) = \frac{15}{2} = 7.5$