Question

In the circuit shown, potential difference between X and Y is ________ and across 40 Ω is ________ .

Answer 1

Given:

A circuit diagram  

 

To find:

In the circuit shown, potential difference between X and Y is ________ and across 40 Ω is ________  

Solution:

From given, we have,

A circuit diagram.

In an open circuit, the potential difference between X and Y will be the same as that of the emf of the cell.

V{X, Y} = EMF of the cell.

Therefore, the potential difference between X and Y is 120 V.

The potential difference across 40 Ω is calculated as follows:

V{40} = [V × R{40}] / [R{40} + R{20}]

V{40} = (120 × 40) / (40 + 20) = 4800/60 = 80 V.

Therefore, the potential difference across 40 Ω is 80 V.

In the circuit shown, the potential difference between X and Y is 120 V and across 40 Ω is 80 V.