Question

In the circuit shown, power generated is maximum in which resistance?
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Answer 1

Maximum power generated in 3 Ω  resistor   = 48W in given circuit

Explanation:

6 Ω  & 3 Ω  are in parallel

Hence their effective resistance

1/R = 1/6  + 1/3

=> 1/R = (1 + 2)/6

=> 1/R  =  3/6

=> 1/R = 1/2

=> R  = 2

Total Resistance =  1 + 2 = 3 Ω

Current in Circuit = 18/3 =  6A

Voltage Drop across 1  Ω  = 6V

Voltage drop across 2Ω = 2 * 6 = 12V

Power generated in 1 Ω  resistor  =   V²/R  = 6²/1  = 36 W

Power generated in 3 Ω  resistor =  12²/3  = 48W

Power generated in 6 Ω  resistor =  12²/6  = 24W

Maximum power generated in 3 Ω  resistor   = 48W

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