Question

In the circuit shown, reading of ammeter is

Answer 1

Answer:

2,3,5 are in series hence net resistance 2+3+5=10 further this 10 and other 5 is connected in parallel as they are joined at the same 2points hence adding parallely their net resistance is 10/3 thus we can replace the complete resistances with one resistor of 10/3 ohm and hence

current i= 5(3)/10=1.5A