Question

In the circuit shown , the current drawn by the cell is

Answer 1

Answer:

Assuming potential at Q is V  

applying KVL loop 1  

9−2i−1(i−i  

1

​  

)−3i=0...(i)

applying KVL loop 2

6−3i  

1

​  

+1(i−i  

1

​  

)=0...(ii)

solving (i) and (ii)

i=1.82A and i  

1

​  

=1.95A

Current through 1Ω resistor =i−i  

1

​  

=−.13A

Therefore, current through 1Ω resistor is 0.13A from Q to P

Answer 2

there is no diagram

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