In the circuit shown, the heat generated in the 4 ohm
resistor due to the current flowing in it is 6 J/s. The
heat generated in the 3 ohm resistor is
(1) 3 joule/second
(3) 18 joule/second
(2) 6 joule/second
(4) 36 joule/second
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Answer:
I think answer is 18
Explanation:
current through 4 ohm resistor is i^2×4=6=√3/√2
voltage between ab =i(2+4)=3√6
heat generated through 3 ohm=(v^2÷3) (3√6)^2÷3=18
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option three is correct......
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