Question

In the circuit shown, the internal resistance of the cell is negligible. The steady state current in the 2Ω resistor is(a) 0.6 A(b) 0.9 A(c) 1.2 A(d) 1.5 A

Answer 1

Answer:

B) 0.9A

Explanation:

In steady state there is no current in capacitor branch, so equivalent circuit is shown in the figure.

Resistance 2Ω  and 3Ω  are grouped in parallel combination. thus the net resistant - 1/2+1/3 = 5/6 = 1.2

As capacitor blocks DC so 4Ω  resistance is of no use.

Resistance R12 is in series with 2.8Ω

The total effective resistance = 1.2+2.8 = 4Ω

Current through circuit I= V/R

= I = 6/4 =  1.5 A  

Therefore the current through 2Ω resistor = 1.5(2+3)×3

= 0.9 A

Thus, the steady state current in the 2Ω resistor is 0.9A