Question

in the circuit shown, the point B is earthed. The potential at
the point A is
​

Answer 1

Answer:

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Answer 2

Answer:

24V

Explanation:

Total resistance = 5+7+10+3 = 25 ohm

Current, I = $\frac{V}{R} = \frac{50}{25}$ = 2A

Potential across AB = $V_{A} - V_{B} = IR = 2. (5+7) = 2 (12) = 24V$

As, point B is earthed, $V_{B} = 0$

So,  $V_{A}-V_{B} = V_{A} - 0 = 24V$

Hence, $V_{A} = 24V$