Question

In the circuit shown, the thermal power dissipated in
R, is P. The thermal power dissipated in R, is
R= R
R=R
WWW
R = 2R​

Answer 1

Explanation:

1/Req = 1/R2 + 1/R3

= 1/R + 1/2R

= 3R / 2R^2

Req = 2R/3

R total = R1 + Req

= R + 2R/3

= 5R/3

Power = I^2 R

= I^2 × 5R/2