Question

In the circuit shown, which is part of a closed circuit, the potential at C is

Answer 1

Answer:

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Answer 2

Answer:

The correct answer is 20 V.

Explanation:

Given :

Current flowing between AC = 1 A

Current flowing between DC = 1 A

Now,

Current flowing between CB,

$i \: = \frac{v - 10}{ 5}$

where i is the current flowing through CB and v is the potential at C.

The above value of i is written by Ohm's law which states that the potential difference between two points is directly proportional to the current flowing through them provided the physical quantities are constant.

Now, Applying Kirchoff's 1st law, which states that at a junction, the coming current is equal to the going current. This law is based on the conservation of charge.

So, at junction C, we have :

current flowing through BC = current flowing through DC + current flowing through AC

$\frac{v - 10}{5} = 1 + 1 = 2 \\ v - 10= 10 \\ v = 10 + 10 = 20$

Hence the potential at C is 20 V.

#SPJ2