In the circuit, the potential difference between A
and B is
(1) 1/10v
(2) 2.5 V
(3) 10 V
(4) 5 V
Answers
Terminal B is missing in ur caption..
plzz atleast pic toh clear uplod kra kro..
In the circuit, the potential difference between A and B is given as follows:
1. Equivalent capacitance for capacitors in series is 1/C = 1/C1 +1/C2.
2. Equivalent capacitance for capacitors in parallel is C =C1 +C2.
3. The equivalent capacitences of 4uF and the two 8uF capacitors is Ceq= 8uF.
4. Capacitors connected in parallel have potentials on the capacitors divided in the inverse ratio of their capacitences.
5. V1 =Ceq*V/(2*Ceq) =16V.
6. Potential at A = 20-16 =4V.
7. V2=2*V/(2*Ceq) =4V.
8. Potential drop across 8uF capacitor os calculated to be 2V.
9. Potential at B =20-16-2 =2V.
10. Hence potential difference between points A and B in the circuit diagram is 4 - 2=2V.
