Question

In the circuit the potential difference between A and B is

Answer 1

Answer:

Explanation:

78

Answer 2

In the circuit, the potential difference between the points A and B is 2 V.

Note: All the options are incorrect.

• The arm AC of the circuit is a parallel combination of two capacitors -

1. 4μF capacitor
2. The series combination of two 8μF capacitors.

• The series combination give an equivalent capacitance of 4μF.
• Now, two 4μF capacitors come in parallel, whose equivalent capacitance is 8μF.
• Now, the 20 V supply is across the series combination of 2μF and 8μF capacitors.
• The total equivalent capacitance of the circuit (Ceq) is 1.6μF.
• The charge Q supplied by the 20 volt source is given by

                               Q=Ceq * V = 1.6 * 20 = 32 μCoulomb

• The voltage across AC is given by

                                    Vac = Q/8μF = 32/8 = 4 Volts.

• Since, Vac is the voltage across the series combination of two 8μF capacitors, the voltage across AB is the half of Vac, i.e,

                                    Vab = Vac/2 = 4/2 = 2 Volts.

Thus, Voltage between A and B is 2 Volts.