In the circuit the power developed in 6ohm resistor is 6watt what is the power in watts developed in 4ohm resistor
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in case 1st
r1=6ohm
p1=6watt
v^2/r=6watt
v^2/6=6watt
v^2=6watt ×6
v=6
now,
in case2,
p=v^2/r
p=6×6/4=36/4=9watts
r1=6ohm
p1=6watt
v^2/r=6watt
v^2/6=6watt
v^2=6watt ×6
v=6
now,
in case2,
p=v^2/r
p=6×6/4=36/4=9watts
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