Question

in the class 125 students,70 play cricket,55 play badminton and 20 play both. How may of them neither play cricket nor badminton

Answer 1

Answer:first you will add 70-20=50

                                             55-20=35

Step-by-step explanation:you will add 50+35=85

then 125-80=45

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Answer 2

Answer:

Step-by-step explanation:

It is given that out of 125 students,  students play none of the sports so the no of students playing atleast one game (cricket or football) is 60–5=55.

Using the Venn diagrams, it can be said that

n(A∪B) =n(A) +n(B) - n(A∩B)

where ,

n(A) is the number of students playing cricket =70

n(B) is the number of students playing badminton =55

n(A∪B) is the number of students playing atleast cricket or badminton=n(A∪B)

n(A∩B) is number of students playing both cricket and badminton should 20. So using above formula

n(A∪B)=55+70-20,

n(A∪B)=55+70–20=125-20

            =105

So the number of students neither playing both games is 105