Question

in the
COMPARE the motion of two bodies
(ase
U Both moving vertically over fortionless pulley.
(in) One body moving vertically and
Other
horizantally​

Answer 1

Explanation:

The given system of two masses and a pulley can be represented as shown in the following figure:

Smaller mass, m1=8 kg

Larger mass,m2=12kg

Tension in the string=T

Mass m2, owing to its weight, moves downward with acceleration, and mass m1 moves upward.

Applying Newton’s second law of motion to the system of each mass:

For mass m1:

The equation of motion can be written as:

T–m1g=ma… (i)

For mass m2:

The equation of motion can be written as:

m2g–T=m2a … (ii)

Adding equations (i) and (ii), we get:

(m2−m1)g=(m1+m2)a

 a=(m1+m2)(m2−m1)g    ....(iii)

=(12+8)(12−8)×10=204×10=2ms−2

Therefore, the acceleration of the masses is 2 m/s2.

Substituting the value of a in equation (ii), we get:

m2g−T=m2(m1+m2)(m2−m1)g

T=(m2−(m1+m2)(m22−m1m2)g

       =(m