Question

In the compound 7-ethyl-3-nonene-2,5,8- tricarboxylic acid, how many atoms are in sp^2- hybridisation state.​

Answer 1

Answer:

solution

, three oxygen atoms and two carbon i.e. hybridization.

Answer 2

Two p orbitals and one s orbital combine to form 3 equivalent orbitals

then the hybridization is known as sp² hybridization.

The compound 7-ethyl-3-nonene-2,5,8- tricarboxylic acid is represented as:

$CH_{3}CH(COOH)CH_{2} CH_{2} CH(COOH)CH_{2}CH(C_{2}H_{5}) CH(COOH)CH_{3}$

The sp² hybridize atoms are:

1. All the carbon of three  $COOH \ are\ sp^{2}$.

2. Three oxygen in $COOH \ are\ sp^{2}$.

3. The C-3 and C-4 $carbons \ are\ sp^{2} .$

Hence, 8 atoms are sp² hybridized in the compound 7-ethyl-3-nonene-2,5,8- tricarboxylic acid.