In the compound N (SiCH3)3 in nitrogen has pyramidal geometry while in compound it is .
Answers
Answer:
In the following molecule (1-(4-fluorophenyl)-4-[[1-(2-methoxyethyl)tetrazol-5-yl]-phenyl-methyl]-piperazine)
enter image description here
I have seen its 3D structure using Jmol, and I see that both nitrogens on the middle ring have either tetrahedral or trigonal pyramidal geometry. I get this, no problem. However, the ring that is made of four nitrogens is entirely planar. Shouldn't it also have some trigonal pyramidal nitrogens too? As for instance, the N on the point connecting to the -OH chain, it has 2 bonds and one unshared pair of electrons, yet it is still planar!
Answer:
N(SiH3)3
has a planar geometry due to back bonding between empty 3d orbital of Si and filled 2p orbital of N. (CH3)3
N has pyramidal geometry due to absence of back bonding. Nitrogen is sp3 hybridized out of which 3 hybrid orbitals are used for bond making and 1 lone pair is present in fourth orbital.