in the concentration of solution which is also coming with 0.02 M solution of any 2 S o4 consume complete dissociation at 30 degree Celsius
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Since two solutions are isotonic, the product of vant Hoff factor i and the concentration C is same. i
Na2SO4
×C
Na2SO4
=iglucose×C
glucose
i
Na2SO4
×0.004M=1×0.010M
i
Na2SO4
=2.5
One molecule of Na
2
SO
4
on dissociation gives three ions
Na
2
SO
4
→2Na
+
+SO
4
2−
n=3
The apparent degree of dissociation of Na
2
SO
4
α=
n−1
i−1
α=
3−1
2.5−1
α=
2
1.5
α=0.75= 75%
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