Question

In the cylindrical container the radius of the base is 8 cm if the height of the water level is 20 cm find the volume of the water in the container​

Answer 1

Answer:

Volume of the water in the container = 4022.86 cm³

Step-by-step explanation:

Given :

• Radius (r) of the base of the cylinder = 8 cm
• Height (h) of the water level = 20 cm

To find :

• Volume of the water in the container.

Solution :

Formula used :

${\boxed{\sf{Volume\:of\: cylinder=\pi\:r^2h}}}$

$\longrightarrow$Volume of the water = (22/7)×8² × 20 cm³

$\longrightarrow$ Volume of the water = (22/7) ×64 ×20 cm³

$\longrightarrow$ Volume of the water = 4022.86 cm³

Therefore, the volume of the water in the container is 4022.86 cm³.

___________________

★ More info :

• TSA of cylinder = 2πr(h+r)
• CSA of cylinder = 2πrh
• Volume of cone = ⅓ πr²h
• TSA of cone = πr(l+r)
• CSA of cone = πrl

Answer 2

$\huge\mathrm{Answer}$

Radius of the base of the cylinder = radius of the cylinder ( r ) = 8 cm

Height of the cylinder ( h ) = 20 cm

Volume of water in the container = volume of water

Volume = πr²h

✍️ Volume = ( 22 × 8 × 8 × 20 ) / 7

✍️ Volume = 28160 / 7

✍️ Volume = 4022.86 cm³

____________________________

⚡ The curved surface area of a cylinder = 2πrh

⚡ The total surface area of cylinder = 2πr ( h + r )

π's value = 3.14 or 22 / 7