Question

In the cylindrical container the radius of the base is 8 cm if the height of the water level is 20 cm find the volume of the water in the container​

Answer 1

Answer:

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• Radius = 8 cm

• Height of cylinder = 240 cm

• Height of conical part = 36 cm

Solution :-

We know that

• Volume of cylinder = πr²h

• Volume of cone = ⅓πr²h

Now,

Volume of cylinder = 3.14 × 8 × 8 × 240

=> 48320.4 cm^3

Now

• ⅓ × 3.14 × 8 × 8 × 36

• 1 × 3.14 × 8 × 8 × 12

• 3.14 × 64 ×12

• 2411.52 cm^3

Now

Weight of pillar = Volume of cylinder + volume of cone

• W = 48320.4 + 2411.52

• W = 50730

Now

• 1kg = 1000gm

• 7.8/1000 × 50730

• 0.0078 × 50730

• 395.4 kg

$\colorbox{color}{Weight of pillar is 395 kg}$

Answer 2

Answer:

Volume of cylinder = r xr? xh

Substituting the values -

= 3.14 x (8)2 x 30

= 3.14 x 64 x 30

= 4021.76

= 4.0218 litres