Question

In the data set, what is the variance? 6 8 1 9 4

Answer 1

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$<i>$
mean = (6+8+1+9+4) / 5 = (14+10+4 ) /5 = 28/5 = 5.6 
so variance = sum of (x-mean)^2/ N for a complete set of data 
but if you treat this as a sample , 
variance = sum of (x-mean)^2/ (N-1) for a sample of data 
If you treat this as a complete data set then: 
Variance = ((6-5.6)^2 + (8-5.6)^2 + (1-5.6)^2 + (9-5.6)^2 + (4-5.6)^2 ) / 5 

Variance= 8.24

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