Question

In the decomposition of KClO3 ,how many moles of KCl are formed in the reaction that produces 0.05 moles of O2

Answer 1

Answer:

0.033 moles

Explanation:

2KClO₃ ---> 2KCl + 3O₂ is the chemical equation

here, for 2 moles of KCl ------ 3 moles of O₂ is produced

hence, for x moles of KCl ------- 0.05 moles of O₂

x = $\frac{0.05*2}{3}$ = 0.1/3= 0.033

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