In the decomposition of lead (II) nitrate to give lead (II) oxide, nitrogen dioxide and oxygen gas, the coefficient of nitrogen dioxide (in the balanced equation) is (a) 1 (b) 2 (c) 3 (d) 4
Answers
Answer:
Option d. In the above chemical reaction, the coefficient of nitrogen oxide which is formed is 4.
Explanation:
Chemical decomposition reaction leads to the breaking down of one compound into two or fragments. The compound lead nitrate breaks down into lead oxide, nitrogen oxide and oxygen. Nitrogen dioxide and oxygen are present in gaseous form whereas the lead oxide is present in solid form.
To balance the equation two compounds of lead nitrate is needed in reactant part and two compounds of lead oxide, four compounds of nitrogen oxide and one compound of oxygen is formed in the product side. The decomposition reaction can be achieved by heating the compound.
Answer:
In the decomposition of lead (II) nitrate to give lead (II) oxide, nitrogen dioxide, and oxygen gas, the coefficient of nitrogen dioxide (in the balanced equation) is 4.
Explanation:
Under the right conditions, a decomposition reaction may be defined as a sort of chemical reaction in which a single component separates into multiple smaller compounds.
The reaction stated above is
2Pb(NO3)2 → 2PbO + 4NO2 + O2
Where lead(II) nitrate decomposes to produce yellow-colored lead (II) oxide, colorless oxygen gas, and brown-colored nitrogen dioxide.
Therefore, in the above-balanced reaction, the coefficient of nitrogen dioxide is 4.
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